给你一个单链表的头节点 head ,请你判断该链表是否为回文链表。如果是,返回 true ;否则,返回 false 。
示例 1:
输入:head = [1,2,2,1]
输出:true
示例 2:
输入:head = [1,2]
输出:false/**
* @param {ListNode} head
* @return {boolean}
*/
//快慢指针从中间分隔链表,翻转后半部分链表,做比较
var isPalindrome = function(head) {
let slow = head;
let fast = head;
while (fast.next && fast.next.next) {
slow = slow.next;
fast = fast.next.next;
}
let right = slow.next;
slow.next = null;
let prev = null;
while (right) {
let next = right.next;
right.next = prev;
prev = right;
right = next;
}
while (prev) {
if (head.val != prev.val) {
return false;
}
head = head.next;
prev = prev.next;
}
return true;
};