给你链表的头结点 head ,请将其按 升序 排列并返回 排序后的链表 。
示例 1:
输入:head = [4,2,1,3]
输出:[1,2,3,4]
示例 2:
输入:head = [-1,5,3,4,0]
输出:[-1,0,3,4,5]
示例 3:
输入:head = []
输出:[]
/**
* @param {ListNode} head
* @return {ListNode}
*/
var sortList = function(head) {
if (!head || !head.next) return head;
let slow = head;
//fast初始不设为起点,而是一个节点,可以保证中间节点位置比较均衡
let fast = head.next;
//快慢指针找到中间节点
while (fast && fast.next) {
slow = slow.next;
fast = fast.next.next;
}
//切断前后半部分
let rightList = slow.next;
slow.next = null;
let left = sortList(head);
let right = sortList(rightList);
return merge(left, right)
};
//合并节点
var merge = function(left, right) {
let dummy = new ListNode(0);
let current = dummy;
while (left && right) {
if (left.val <= right.val) {
current.next = left;
left = left.next;
} else {
current.next = right;
right = right.next;
}
current = current.next;
}
current.next = left ? left : right;
return dummy.next;
}